SATHEE: Redox Reactions And Electrochemistry Ques 360

Redox Reactions And Electrochemistry Ques 360

Question: If 10 g of $V_{2} O_{5}$ , is dissolved in acid and is reduced to $V^{2 +}$ by zinc metal, how many mole of I, could be reduced by the resulting solution if it is further oxidised to $V O^{2 +}$ ions- [Assume no change in state of $Z n^{2 +}$ ions] (V=51,O=16, I=127):

Options:

A) 0.11 mole of $I_{2}$

B) 0.22 mole of $I_{2}$

C) 0.055 mole of $I_{2}$

D) 0.44 mole of $I_{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $\underset{+ 5}{V_{2} O_{5}}, + 6 e^{-} \to \underset{+ 2}{2 V^{2 +}},$ Molecular mass of $V_{2} O_{5} = 51 \times 2 + 5 \times 16 = 182$ 1 mol of $V_{2} O_{5}$ produces 2 moles of $V^{2 +}$

$∴ \frac{10}{182}$ moles of $V_{2} O_{5}$ produce $2 \times \frac{10}{182} = 0.11$ moles of $V^{2 +}$ $\underset{+ 2}{V^{2 +}}, \to V {\underset{0}{O},}^{2 +} + 2 e^{-}$ (1)

$\underset{0}{I_{2}}, + 2 e^{-} \to \underset{- 1}{2 I^{-}},$ (2)

On adding (1) and (2) $V^{2 +} + I_{2} \to 2 I^{-} + V O^{2 +}$ 1 mole of $V^{2 +}$ reduces 1 mole of $I_{2}$

$∴ 0.11$ moles of $V^{2 +}$ reduce 0.11 moles of $I_{2}$

Redox Reactions And Electrochemistry Ques 360

Question: If 10 g of $V_{2} O_{5}$ , is dissolved in acid and is reduced to $V^{2 +}$ by zinc metal, how many mole of I, could be reduced by the resulting solution if it is further oxidised to $V O^{2 +}$ ions- [Assume no change in state of $Z n^{2 +}$ ions] (V=51,O=16, I=127):

Options:

Answer:

Solution:

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Redox Reactions And Electrochemistry Ques 360

Question: If 10 g of V2O5 , is dissolved in acid and is reduced to V2+ by zinc metal, how many mole of I, could be reduced by the resulting solution if it is further oxidised to VO2+ ions- [Assume no change in state of Zn2+ ions] (V=51,O=16, I=127):

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: If 10 g of $V_{2} O_{5}$ , is dissolved in acid and is reduced to $V^{2 +}$ by zinc metal, how many mole of I, could be reduced by the resulting solution if it is further oxidised to $V O^{2 +}$ ions- [Assume no change in state of $Z n^{2 +}$ ions] (V=51,O=16, I=127):