Redox Reactions And Electrochemistry Ques 344

Question: The standard emf of a cell having one electron change found to be 0.591 V at $ 25{}^\circ C $ . The equilibrium constant the reaction is

Options:

A) $ 1.0\times 10^{30} $

B) $ 1.0\times 10^{5} $

C) $ 1.0\times 10^{10} $

D) $ 1.0\times 10^{1} $

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Answer:

Correct Answer: C

Solution:

[c] $ E_{cell}=E^o_{cell}-\frac{0.059}{n}\log Q $ At equilibrium, $ E_{cell}=0 $ and $ Q=K_{c} $ $ E^o_{cell}=\frac{0.059}{1}\log K_{c} $
$ \Rightarrow 0.591=\frac{0.059}{1}\log K_{c} $
$ \therefore K_{c}=1\times 10^{10} $



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