Redox Reactions And Electrochemistry Ques 337

Question: Electrode potential data are given below. $ F{e^{3+}}~( aq )\text{+}{e^{-}}\to F{e^{2+}}( aq ); $ $ E{}^\circ =+,0.77 $ $ A{l^{3+}}( aq )\text{+3}{e^{-}}\to \text{Al(s);} $ $ E{}^\circ =-,1.66V $ $ Br_2(aq)+2{e^{-}}\to 2B{r^{-}}(aq); $ $ E{}^\circ =+,1.08V $ Based on the data given above, reducing power of $ F{e^{2+}} $ , Al and $ B{r^{-}} $ will increase in the order

Options:

A) $ B{r^{-}}<F{e^{2+}}<Al $

B) $ F{e^{2+}}<Al<B{r^{-}} $

C) $ Al<B{r^{-}}<F{e^{2+}} $

D) $ Al<F{e^{2+}}<B{r^{-}} $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] The lowest the standard reduction potential, the highest is the reducing power.



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