SATHEE: Redox Reactions And Electrochemistry Ques 330

Redox Reactions And Electrochemistry Ques 330

Question: Molar conductance’s of $B a C l_{2,}$ $H_{2} S O_{4}$ , and HCl at infinite dilutions are $x_{1}$ , $x_{2}$ , and $x_{3}$ , respectively. Equivalent conductance of $B a S O_{4}$ at infinite dilution will be:

Options:

A) $\frac{[x_{1} + x_{2} - x_{3}]}{2}$

B) $\frac{[x_{1} - x_{2} - x_{3}]}{2}$

C) $2 (x_{1} + x_{2} - 2 x_{3})$

D) $\frac{[x_{1} + x_{2} - 2 x_{3}]}{2}$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $Λ_{m, B a C l_{2}} = {Λ_{m}}_{B a^{2 +}} + 2 Λ_{m C l^{-}} x_{1}$

$Λ_{m, H_{2} S O_{4}} = 2 Λ_{m H^{+}} + {Λ_{m}}_{S {O^{-}}_{4}} x_{2}$

$Λ_{m H C l} = Λ_{m H^{+}} + {Λ_{m}}_{C l^{-}} x_{2}] \times 2$

$∴ \land_{m, B a S O_{4}} = (x_{1} + x_{2} - 2 x_{3})$

$\Rightarrow \land_{e q . B a S O_{4}} = \frac{\land_{m, B a S O_{4}}}{T o t a l c h a r g e (cation/anion)}$

$\land_{e q . B a S O_{4}} = \frac{[x_{1} + x_{2} - 2 x_{3}]}{2}$

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Redox Reactions And Electrochemistry Ques 330

Question: Molar conductance’s of BaCl2, H2SO4 , and HCl at infinite dilutions are x1 , x2 , and x3 , respectively. Equivalent conductance of BaSO4 at infinite dilution will be:

Options:

Answer:

Solution:

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Question: Molar conductance’s of $B a C l_{2,}$ $H_{2} S O_{4}$ , and HCl at infinite dilutions are $x_{1}$ , $x_{2}$ , and $x_{3}$ , respectively. Equivalent conductance of $B a S O_{4}$ at infinite dilution will be: