Redox Reactions And Electrochemistry Ques 328
Question: Given $ l\text{/}a=0.5,c{m^{-1}} $ , R = 50 ohm, N = 1.0. The equivalent conductance of the electrolytic cell is
Options:
A) $ 100,oh{m^{-1}}cm^{2}g,E{q^{-1}} $
B) $ 20,oh{m^{-1}}cm^{2}g,E{q^{-1}} $
C) $ 300,oh{m^{-1}}cm^{2}g,E{q^{-1}} $
D) $ 10,oh{m^{-1}}cm^{2}g,E{q^{-1}} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ l/a=0.5,c{m^{-1}},R=50,\Omega $ $ \rho =\frac{Ra}{l}=\frac{50}{0.5}=100 $
$ A=k\times \frac{1000}{N}=\frac{1}{\rho }\times \frac{1000}{N}=\frac{1}{100}\times \frac{1000}{1} $
$ =10,oh{m^{-1}}cm^{2}g,E{q^{-1}} $
