Redox Reactions And Electrochemistry Ques 298

Question: The number of electrons passing per second through a cross-section of copper wire carrying $ {10^{-6}} $ amperes of current per second is found to be [EAMCET 1985]

Options:

A) $ 1.6\times {10^{-19}} $

B) $ 6\times {10^{-35}} $

C) $ 6\times {10^{-16}} $

D) $ 6\times 10^{12} $

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Answer:

Correct Answer: D

Solution:

Charge (Coulombs) pass per second $ ={10^{-6}} $ number of electrons passed per second $ =\frac{{10^{-6}}}{1.602\times {10^{-19}}}=6.24\times 10^{12} $ .



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