Redox Reactions And Electrochemistry Ques 270

Question: On passing 0.1 Faraday of electricity through aluminium chloride, the amount of aluminium metal deposited on cathode is $ (Al=27) $ [MP PMT 1991]

Options:

A) 0.9 gm

B) 0.3 gm

C) 0.27 gm

D) 2.7 gm

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Answer:

Correct Answer: A

Solution:

At cathode; $ A{l^{3+}}+3{e^{-}}\to Al $ $ E_{Al}=\frac{27}{3}=9 $ $ W_{Al}=E_{Al}\times No\text{.},of,faradays $ $ =9\times 0.1=0.9,gm $ .



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