Redox Reactions And Electrochemistry Ques 270
Question: On passing 0.1 Faraday of electricity through aluminium chloride, the amount of aluminium metal deposited on cathode is $ (Al=27) $ [MP PMT 1991]
Options:
A) 0.9 gm
B) 0.3 gm
C) 0.27 gm
D) 2.7 gm
Show Answer
Answer:
Correct Answer: A
Solution:
At cathode; $ A{l^{3+}}+3{e^{-}}\to Al $ $ E_{Al}=\frac{27}{3}=9 $ $ W_{Al}=E_{Al}\times No\text{.},of,faradays $ $ =9\times 0.1=0.9,gm $ .
