Redox Reactions And Electrochemistry Ques 213
Question: The standard e.m.f. of a call, involving one electron change is found to be $ 0.591\ V $ at 25°C. The equilibrium constant of the reaction is ( $ F=96,500\ C\ mo{l^{-1}}; $ $ R=8.314\ J{K^{-1}}mo{l^{-1}}) $ [AIEEE 2004]
Options:
A) $ 1.0\times 10^{10} $
B) $ 1.0\times 10^{5} $
C) $ 1.0\times 10^{1} $
D) $ 1.0\times 10^{30} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ E_{Cell}=E_{cell}^{0}-\frac{0.0591}{n}\log K_{c} $ At 298 K $ E_{Cell}=0 $ $ O=0.591-\frac{0.0591}{n}\log K_{c} $ $ \log K_{c}=\frac{0.591\times 1}{0.0591}=10 $ ; $ K_{c}=\text{Anti }\log 10=1\times 10^{10} $ .
