SATHEE: Redox Reactions And Electrochemistry Ques 211

Redox Reactions And Electrochemistry Ques 211

Question: In a cell that utilises the reaction $Z n_{(s)} + 2 H^{+} (a q) \to$ $Z n^{2 +} (a q) + H_{2 (g)}$ addition of $H_{2} S O_{4}$ to cathode compartment, will [AIEEE 2004]

Options:

A) Increase the E and shift equilibrium to the right

B) Lower the E and shift equilibrium to the right

C) Lower the E and shift equilibrium to the left

D) Increase the E and shift equilibrium to the left

Show Answer

Answer:

Correct Answer: A

Solution:

$Z n_{(s)} + 2 {H^{+}}_{(a q)}$ - $Z n_{(a q)}^{2 +} + H_{2 (g)}$

$E_{C e l l} = E_{c e l l}^{0} - \frac{.059}{2} \log \frac{[Z n^{2 +}]}{{[H^{+}]}^{2}}$

When $H_{2} S O_{4}$ is added then $[H^{+}]$ will increase therefore $E_{C e l l}$ will also increases and equilibrium will shift towards right.

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Redox Reactions And Electrochemistry Ques 211

Question: In a cell that utilises the reaction Zn(s)+2H+(aq)→ Zn2+(aq)+H2(g) addition of H2SO4 to cathode compartment, will [AIEEE 2004]

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Question: In a cell that utilises the reaction $Z n_{(s)} + 2 H^{+} (a q) \to$ $Z n^{2 +} (a q) + H_{2 (g)}$ addition of $H_{2} S O_{4}$ to cathode compartment, will [AIEEE 2004]