Redox Reactions And Electrochemistry Ques 182
Question: $ Z{n^{2+}}+2{e^{-}}\to Zn(s);E^{o}=-,0.76 $ , $ F{e^{3+}}+{e^{-}}\to F{e^{2+}};E^{o}=-,0.77 $ , $ C{r^{3+}}+3{e^{-}}\to Cr;E^{o}=-,0.79 $ , $ {H^{+}}+2{e^{-}}\to 1/2H_2,;,E^{o}=0.00 $ Strongest reducing agent is [BHU 2003]
Options:
A) $ F{e^{2+}} $
B) $ Zn $
C) $ Cr $
D) $ H_2 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ C{r^{3+}}>Z{n^{2+}}>H>F{e^{3+}} $ . Reducing nature decreasing order.
