Redox Reactions And Electrochemistry Ques 130
Question: The correct representation of Nernst’s equation is
Options:
A) $ {E_{{M^{n+}}/M}}=E^o_{{M^{n+}}/M}+\frac{0.0591}{n}\log ,({M^{n+}}) $
B) $ {E_{{M^{n+}}/M}}=E^o_{{M^{n+}}/M}-\frac{0.0591}{n}\log ,({M^{n+}}) $
C) $ {E_{{M^{n+}}/M}}=E^o_{{M^{n+}}/M}+\frac{n}{0.0591}\log ,({M^{n+}}) $
D) None of the above
Show Answer
Answer:
Correct Answer: A
Solution:
$ E=E^{o}-\frac{RT}{nF}\ln \frac{1}{[{M^{n+}}]} $ ; $ E=E^{o}+\frac{RT}{nF}\ln [{M^{n+}}] $ $ E=E^{o}+\frac{2.303RT}{nF}\log [{M^{n+}}] $ Substituting the value of R, T (298K) and F we get $ E=E^{o}+\frac{0.0591}{n}\log ({M^{n+}}) $ .
