Redox Reactions And Electrochemistry Ques 121
Question: The hydrogen electrode is dipped in a solution of $ pH=3 $ at $ 25^{o}C $ . The potential of the cell would be (the value of $ 2.303RT/F $ is 0.059 V) [KCET 1993,2005]
Options:
A) 0.177 V
B) - 0.177 V
C) 0.087 V
D) 0.059 V
Show Answer
Answer:
Correct Answer: B
Solution:
Reduction potential of hydrogen electrode, $ E_{H}=\frac{-2.303,RT}{F}\log \frac{1}{[{H^{+}}]} $ $ =-0.059,pH=-0.059\times 3=-0.177,V $ .
