A) No action takes place
B) $ NaAlO_2 $ is formed and $ H_2 $ is evolved
C) $ Al{{( OH )}_3} $ is formed and $ H_2 $ is evolved
D) $ Na_2AlO_2 $ is formed and $ H_2 $ is evolved
Correct Answer: B
$ Al+NaOH+H_2O\to NaAlO_2+H_2\uparrow . $
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