A) By donating $ {{H}^{+}} $
B) By accepting $ O{{H}^{-}} $
C) By donating lone pair of electrons
D) By accepting lone pair of electrons.
Correct Answer: B
$ B{{(OH)}_3}+2H_2O\rightarrow {{[B{{(OH)}_4}]}^{-}}+H_3{{O}^{+}} $
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