P-Block Elements Ques 457

Question: When $ SO_2 $ is passed through acidified $ K_2Cr_2O_7 $ solution

[CPMT 1989, 94]

Options:

A) The solution turns blue

B) The solution is decolourised

C) $ SO_2 $ is reduced

D) Green $ Cr_2{{(SO_4)}_3} $ is formed

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Answer:

Correct Answer: D

Solution:

$ K_2Cr_2O_7+H_2SO_4+3SO_2\to $ $ K_2SO_4+\underset{Green}{\mathop{Cr_2{{(SO_4)}_3}}}+3H_2O $



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