P-Block Elements Ques 437
Question: The oxidation number of xenon in $ XeOF_2 $ is
[J & K 2005]
Options:
A) Zero
B) 2
C) 4
D) 3
Show Answer
Answer:
Correct Answer: C
Solution:
Suppose the oxidation state of $ Xe $ is $ x $ . $ XeOF_2 $ $ x+(-2)+2(-1)=0 $
Therefore $ x-2-2=0 $
Therefore $ x=4 $ .