P-Block Elements Ques 437

Question: The oxidation number of xenon in $ XeOF_2 $ is

[J & K 2005]

Options:

A) Zero

B) 2

C) 4

D) 3

Show Answer

Answer:

Correct Answer: C

Solution:

Suppose the oxidation state of $ Xe $ is $ x $ . $ XeOF_2 $ $ x+(-2)+2(-1)=0 $ Therefore $ x-2-2=0 $
Therefore $ x=4 $ .



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