P-Block Elements Ques 169
Question: What is the product obtained in the reaction of $ HgCl_2 $ and $ Hg{{(CN)}_2} $
[MP PET 2002]
Options:
A) $ {{(CN)}_2} $
B) Addition compound $ HgCl_2.Hg{{(CN)}_2} $
C) $ Hg(CN)Cl $
D) $ Hg[Hg{{(CN)}_2}Cl_2] $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{Mercuricchloride}{\mathop{HgCl_2}}+\underset{Mercuriccyanide}{\mathop{Hg{{(CN)}_2}}}\to HgCl_2.Hg{{(CN)}_2} $
