SATHEE: Equilibrium Question 912

Equilibrium Question 912

Question: What is the minimum pH when $F e {(O H)}_{3},$ starts precipitating from a solution containing $0.1 M F e C l_{3}$ - $k_{s p}$ of $F e {(O H)}_{3} = 8 \times 10^{- 13} M^{3} (\log 2 = 0.3)$

Options:

A) 3.7

B) 5.7

C) 10.3

D) 8.3

Show Answer

Answer:

Correct Answer: C

Solution:

$8 \times 10^{- 13} = [F e^{3 +}] {[O - H]}^{3}$

$[O H^{-}] = 2 \times 10^{- 4}$

$p O H = 4 - \log 2 = 3.7$

$p H = 10.3$

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Equilibrium Question 912

Question: What is the minimum pH when Fe(OH)3, starts precipitating from a solution containing 0.1MFeCl3 - ksp of Fe(OH)3=8×10−13M3(log⁡2=0.3)

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Question: What is the minimum pH when $F e {(O H)}_{3},$ starts precipitating from a solution containing $0.1 M F e C l_{3}$ - $k_{s p}$ of $F e {(O H)}_{3} = 8 \times 10^{- 13} M^{3} (\log 2 = 0.3)$