SATHEE: Equilibrium Question 909

Equilibrium Question 909

Question: Arrange the following in increasing order of $p H K N O_{3} (a q),, C H_{3} C O O N (a q),$

$N H_{4} C l (a q),, C_{6} H_{5} C O O N H_{4} (a q)$

Options:

A) $C H_{3} C O O N a < C_{6} H_{5} C O O N H_{4}$ $< N H_{4} C l < K N O_{3}$

B) $K N O_{3} < N H_{4} C < C H_{3} C O O N a$ $< C_{6} H_{5} C O O N a$

C) $N H_{4} C l < K N O_{3} < C H_{3} C O O N a$ $< C_{6} H_{5} C O O N H_{4}$

D) $N H_{4} C l < K N O_{3} < C_{6} H_{5} C O O N H_{4}$ $< C H_{3} C O O N a$

Show Answer

Answer:

Correct Answer: D

Solution:

(i) $K N O_{3}$ is a salt of strong acid and strong base, hence its aqueous solution is neutral; pH = 7

(ii) $C H_{3} C O O N a$ is a salt of weak acid and strong base/hence, its aqueous solution is basic ; pH > 7

(iii) $N H_{4} C l$ is a salt of strong acid and weak base, hence its aqueous solution is acidic; pH < 7

(iv) $C_{6} H_{5} C O O N H_{4}$ is a salt of weak acid, $C_{6} H_{5} C O O H$ and weak base, $N H_{4} O H$ . But $N H_{4} O H$ is slightly stronger than $C_{6} H_{5} C O O H$ . Hence, pH is slightly > 7.

Therefore, increasing order of pH of the given salts is $< C H_{3} C O O N a$

Equilibrium Question 909

Question: Arrange the following in increasing order of $p H K N O_{3} (a q),, C H_{3} C O O N (a q),$

Options:

Answer:

Solution:

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Equilibrium Question 909

Question: Arrange the following in increasing order of pHKNO3(aq),,CH3COON(aq),

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Arrange the following in increasing order of $p H K N O_{3} (a q),, C H_{3} C O O N (a q),$