SATHEE: Equilibrium Question 906

Equilibrium Question 906

Question: A mixture of weak acid is $0.1 M$ in $H C O O H$

$(K_{a} = 1.8 \times 10^{- 4})$ and $0.1 M$ in $H O C N (K_{a} = 3.1 \times 10^{- 4})$ Hence, $[H_{3} O^{\oplus}]$ is

Options:

A) $7.0 \times 10^{- 3} M$

B) $4.1 \times 10^{- 4} M$

C) $0.20 M$

D) $4.1 \times 10^{- 3} M$

Show Answer

Answer:

Correct Answer: A

Solution:

$[H_{3} O^{+}] = \sqrt{K_{1} C_{1} + K_{2} C_{2}}$

$= \sqrt{1.8 \times 10^{- 4} \times 0.1 + 3.1 \times 10^{- 4} \times 0.1}$

$= 7 \times 10^{- 3} M$

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