SATHEE: Equilibrium Question 903

Equilibrium Question 903

Question: 100 mL of 1 M $H C l$ is mixed with 50 mL of 2 M $H C l$ . Hence, $[H_{3} O^{+}]$ is:

Options:

A) 1.00 M

B) 1.50 M

C) 1.33 M

D) 3.00 M

Show Answer

Answer:

Correct Answer: C

Solution:

Resultant $[H^{+}] =$

$\frac{M_{1} V_{1} + M_{2} V_{2}}{V_{1} + V_{2}} = \frac{100 + 100}{150} = 1.33 M$

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Equilibrium Question 903

Question: 100 mL of 1 M HCl is mixed with 50 mL of 2 M HCl . Hence, [H3O+] is:

Options:

Answer:

Solution:

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Question: 100 mL of 1 M $H C l$ is mixed with 50 mL of 2 M $H C l$ . Hence, $[H_{3} O^{+}]$ is: