SATHEE: Equilibrium Question 903

Equilibrium Question 903

Question: 100 mL of 1 M $ HCl $ is mixed with 50 mL of 2 M $ HCl $ . Hence, $ [ H_3{O^{+}} ] $ is:

Options:

A) 1.00 M

B) 1.50 M

C) 1.33 M

D) 3.00 M

Show Answer

Answer:

Correct Answer: C

Solution:

Resultant $ [{H^{+}}]= $

$ \frac{M_1V_1+M_2V_2}{V_1+V_2}=\frac{100+100}{150}=1.33M $

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Equilibrium Question 903

Question: 100 mL of 1 M $ HCl $ is mixed with 50 mL of 2 M $ HCl $ . Hence, $ [ H_3{O^{+}} ] $ is:

Options:

Answer:

Solution:

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