SATHEE: Equilibrium Question 900

Equilibrium Question 900

Question: Match List I with List II and select the correct answer using the code given below the lists

List I	List II
[A] pH of 0.1 M HA $(p K_{a} = 5)$ and 0.01 M NaA	(p) 4
[B] pH of 0.1 M BOH $(p K_{b} = 6)$ and 0.1 M BCI	(q) 7
[C] pH of 0.1 M salt of HA $(p K_{a} = 5)$ and BOH $(p K_{b} = 7)$	(r) 6
[D] pH of 500 litre of 0.2 M $H N O_{3}$ and 500 litre 0.2 M NaOH	(s) 8

Codes:

Options:

A) A $\to$ p, B $\to$ s, C $\to$ r, D $\to$ q

B) A $\to$ s, B $\to$ p, C $\to$ r, D $\to$ q

C) A $\to$ p, B $\to$ r, C $\to$ s, D $\to$ q

D) A $\to$ p, B $\to$ s, C $\to$ q, D $\to$ r

Show Answer

Answer:

Correct Answer: A

Solution:

$p H = p K_{a} + \log_{10} [\frac{S a l t}{A c i d}] =$

$5 + \log_{10} [\frac{0.1}{0.01}] = 4$

[b] $p O H = p K_{b} + \log_{10} [\frac{0.1}{0.1}] = 6$

$p H = 14 - 6 = 8$

[c] $p H = \frac{1}{2} [p K_{w} + p K_{a} - p K_{b}] =$

$\frac{1}{2} [14 + 5 - 7] = 6$

[d] Neutral solution $p H = 7$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Equilibrium Question 900

Question: Match List I with List II and select the correct answer using the code given below the lists

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu