SATHEE: Equilibrium Question 893

Equilibrium Question 893

Question: pH of an aqueous solution of HCl is 5. if 1 c.c. of this solution is diluted to 1000 times. The pH will become

Options:

A) 8

B) 5

C) 6.9

D) None

Show Answer

Answer:

Correct Answer: C

Solution:

pH of HCl solution = 5 ${[H^{+}]}_{i n i t i a l} = 10^{- 5}$

${[H^{+}]}_{i n i t i a l} \times V_{1} = {[H^{+}]}_{f i n a l} \times V_{2}$

${[H^{+}]}_{f i n a l} \times 10^{- 8}$

Let the $H^{+}$ from water be x. $H_{2} O \to \underset{x + 10^{- 8}}{H^{+}}, + \underset{x}{O H^{-}},$

$x (x + 10^{- 8}) = 10^{- 14}$

$x^{2} + 10^{- 8} - 10^{- 14} = 0$

$x = \frac{- 10^{- 8} \pm \sqrt{10^{- 16} = 4 \times 10^{- 14}}}{2}$

$\Rightarrow$ $x = \frac{- 10^{- 8} + 10^{- 8} \sqrt{401}}{2} = 19 \times 10^{- 8} = 9.5 \times 10^{- 8}$

${[H^{+}]}_{T o t a l} = {[H^{+}]}_{H C l} + {[H^{+}]}_{W a t e r}$

$= 10^{- 8} + 10^{- 8} \times 9.5 = 10.5 \times 10^{- 8}$

$p H = 8 - \log, 10.5$

Slightly less then 7 Hence [c].

Equilibrium Question 893

Question: pH of an aqueous solution of HCl is 5. if 1 c.c. of this solution is diluted to 1000 times. The pH will become

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

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Other Resources

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Sample Mock Test

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NCERT Exercise Video Solution

Equilibrium Question 893

Question: pH of an aqueous solution of HCl is 5. if 1 c.c. of this solution is diluted to 1000 times. The pH will become

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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