Equilibrium Question 870
Question: Calculate $ \Delta G{}^\circ $ for conversion of oxygen to ozone $ 3/2\ O_2(g)\to O_3(g) $ at 298 K, if $ K_{p} $ for this conversion is $ 2.47\times {10^{-29}} $
Options:
A) $ 163\ kJ\ mo{l^{-1}} $
B) $ 2.4\times 10^{2}\ kJ\ mo{l^{-1}} $
C) $ 1.63\ kJ\ mo{l^{-1}} $
D) $ 2.38\times 10^{6}\ kJ\ mo{l^{-1}} $
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Answer:
Correct Answer: A
Solution:
As we know that, $ \Delta G^{o}=-2.303RT,\log ,K_{p} $
Therefore, $ \Delta G^{o}=-2.303\times (8.314)\times (298), $
$ (\log ,2.47\times {10^{-29}}) $
$ \Delta G^{o}=16,3000,J,mo{l^{-1}} $
$ =163,KJ,mo{l^{-1}} $