Equilibrium Question 864

Question: 15 moles of $ H_2 $ and 5.2 moles of $ I_2 $ are mixed and allowed to attain equilibrium at $ 500^{o}C $ . At equilibrium, the concentration of $ HI $ is found to be 10 moles. The equilbrium constant for the formation of $ HI $ is

Options:

A) 50

B) 15

C) 100

D) 25

Show Answer

Answer:

Correct Answer: A

Solution:

$ H_2 $ + $ I_2 $

$ \rightarrow $ $2HI $

15 5.2 0 (15–5) (5.2–5) 10 $ K_{C}=\frac{{{[HI]}^{2}}}{[H_2][I_2]}=\frac{10\times 10}{10\times 0.2}=50 $



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