Equilibrium Question 854
Question: Solid $ AgNO_3 $ is slowly added to a solution containing each of 0.01M $ NaCl $ and 0.001 M $ NaBr. $ What will be the concentration of $ {C^{-}} $ ions in solution when $ AgBr $ will just start to precipitate- $ K _{sp}(AgBr)=3.6\times {10^{-13}},K _{sp}(AgCl)=1.8\times {10^{-10}}. $
Options:
A) $ 1.8\times {10^{-7}} $
B) $ 3.6\times {10^{-10}} $
C) 0.01
D) $ 2\times {10^{-4}} $
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Answer:
Correct Answer: C
Solution:
$ K _{sp}(AgBr)<K _{sp}(AgCl) $ Therefore, $ AgBr $ will precipitate first and at that time all $ C{l^{-}} $ will be present.