Equilibrium Question 818
Question: $ NaOH $ is a strong base. What will be pH of $ 5.0\times {10^{-2}}M,NaOH $ solution’ $ ( log2=0.3 ) $
Options:
A) 14.00
B) 13.70
C) 13.00
D) 12.70
Show Answer
Answer:
Correct Answer: D
Solution:
Given $ [ O{H^{-}} ]=5\times {10^{-2}} $
$ \therefore pOH=-log5\times {10^{-2}} $
$ =-log5+2log10=1.30 $
$ \therefore pH+pOH=14 $
$ \therefore pH=14-pOH $
$ =14-1.30=12.70 $
