SATHEE: Equilibrium Question 818

Equilibrium Question 818

Question: $N a O H$ is a strong base. What will be pH of $5.0 \times 10^{- 2} M, N a O H$ solution’ $(l o g 2 = 0.3)$

Options:

A) 14.00

B) 13.70

C) 13.00

D) 12.70

Show Answer

Answer:

Correct Answer: D

Solution:

Given $[O H^{-}] = 5 \times 10^{- 2}$

$∴ p O H = - l o g 5 \times 10^{- 2}$

$= - l o g 5 + 2 l o g 10 = 1.30$

$∴ p H + p O H = 14$

$∴ p H = 14 - p O H$

$= 14 - 1.30 = 12.70$

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Equilibrium Question 818

Question: NaOH is a strong base. What will be pH of 5.0×10−2M,NaOH solution’ (log2=0.3)

Options:

Answer:

Solution:

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Question: $N a O H$ is a strong base. What will be pH of $5.0 \times 10^{- 2} M, N a O H$ solution’ $(l o g 2 = 0.3)$