SATHEE: Equilibrium Question 785

Equilibrium Question 785

Question: The ratio $\frac{K_{p}}{K_{c}}$ for the reaction $C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)$ is:

Options:

A) $\frac{1}{\sqrt{R T}}$

B) ${(R T)}^{1 / 2}$

C) RT

D) 1

Show Answer

Answer:

Correct Answer: A

Solution:

$K_{p} = K_{C} {(R T)}^{Δ n};$ For the reaction $C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)$

$Δ n_{g} = 1 - (1 + \frac{1}{2}) = - \frac{1}{2}$

$∴ K_{p} = \frac{K_{C}}{\sqrt{R T}};, \frac{K_{p}}{K_{C}} = \frac{1}{\sqrt{R T}}$

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