Equilibrium Question 781

Question: For the reaction: $ 2BaO_2(s)\rightarrow 2BaO(s)+O_2(g); $

$ \Delta H=+ve. $ In equilibrium condition, pressure of $ O_2 $ is dependent on

Options:

A) mass of $ BaO_2 $

B) mass of $ BaO $

C) temperature of equilibrium

D) mass of $ BaO_2 $ and $ BaO $ both

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Answer:

Correct Answer: C

Solution:

For the reaction $ 2BaO_2(s)\rightarrow 2BaO(s)+O_2(g);\Delta H=+ve $ At equilibrium $ K_{p}={P_{O_2 }} $ Hence, the value of equilibrium constant depends only upon partial pressure of $ O_2 $ . Further on increasing temperature formation of $ O_2 $ increases as this is an endothermic reaction. Hence, pressure of $ O_2 $ is dependent on temperature.



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