SATHEE: Equilibrium Question 743

Equilibrium Question 743

Question: Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the $H^{+}$ ion concentration

Options:

A) $3.7 \times 10^{- 3} M$

B) $1.11 \times 10^{- 3} M$

C) $1.11 \times 10^{- 4} M$

D) $3.7 \times 10^{- 4} M$

Show Answer

Answer:

Correct Answer: D

Solution:

$[H^{+}] = 10^{- 3} M, [H^{+}] = 10^{- 4} M, [H^{+}] = 10^{- 5} M$ for the given acids. $M_{m i x} V_{m i x} = M_{1} V_{1} + M_{2} V_{2} + M_{3} V_{3}$

$M_{m i x} \times 3 = 10^{- 3} \times 1 + 10^{- 4} \times 1 + 10^{- 5} \times 1$

$M_{m i x} = \frac{10^{- 5} [100 + 10 + 1]}{3} = \frac{111 \times 10^{- 5}}{3}$

$= 37 \times 10^{- 5} M = 3.7 \times 10^{- 4} M$

Equilibrium Question 743

Question: Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the $H^{+}$ ion concentration

Options:

Answer:

Solution:

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Equilibrium Question 743

Question: Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the H+ ion concentration

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the $H^{+}$ ion concentration