SATHEE: Equilibrium Question 741

Equilibrium Question 741

Question: If $p K_{b}$ A for fluoride ion at $25^{\circ} C$ is 10.83, (he ionization constant of hydrofluoric acid in water at this temperature is

Options:

A) $1.74 \times 10^{- 5}$

B) $3.52 \times 10^{- 3}$

C) $6.75 \times 10^{- 4}$

D) $5.38 \times 10^{- 2}$

Show Answer

Answer:

Correct Answer: C

Solution:

$H F + H_{2} O \to F^{-} + H_{3} O^{+}$

$K_{a} \times K_{b} = K_{w}$

$p K_{a} + p K_{b} = p K_{w}$

$p K_{a} = 14 - 10.83 \Rightarrow p K_{a} = 3.17$

$K_{a} = 6.75 \times 10^{- 4}$

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Equilibrium Question 741

Question: If pKb A for fluoride ion at 25∘C is 10.83, (he ionization constant of hydrofluoric acid in water at this temperature is

Options:

Answer:

Solution:

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Question: If $p K_{b}$ A for fluoride ion at $25^{\circ} C$ is 10.83, (he ionization constant of hydrofluoric acid in water at this temperature is