SATHEE: Equilibrium Question 657

Equilibrium Question 657

Question: What is the equilibrium expression for the reaction $P_{4 (s)} + 5 O_{2 (g)}$ ⇌ $P_{4} O_{10 (s)}$ [AIEEE 2004]

Options:

A) $K_{c} = {[O_{2}]}^{5}$

B) $K_{c} = [P_{4} O_{10}] / 5 [P_{4}] [O_{2}]$

C) $K_{c} = [P_{4} O_{10}] / [P_{4}] {[O_{2}]}^{5}$

D) $K_{c} = 1 / {[O_{2}]}^{5}$

Show Answer

Answer:

Correct Answer: D

Solution:

$P_{4} (s) + 5 O_{2} (g)$ ⇌ $P_{4} O_{10} (s)$

$K_{c} = \frac{[P_{4} O_{10} (s)]}{[P_{4} (s)] {[O_{2} (g)]}^{5}}$ We know that concentration of a solid component is always taken as unity $K_{c} = \frac{1}{{[O_{2}]}^{5}}$

Equilibrium Question 657

Question: What is the equilibrium expression for the reaction $P_{4 (s)} + 5 O_{2 (g)}$ ⇌ $P_{4} O_{10 (s)}$ [AIEEE 2004]

Options:

Answer:

Solution:

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Equilibrium Question 657

Question: What is the equilibrium expression for the reaction P4(s)+5O2(g) ⇌ P4O10(s) [AIEEE 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: What is the equilibrium expression for the reaction $P_{4 (s)} + 5 O_{2 (g)}$ ⇌ $P_{4} O_{10 (s)}$ [AIEEE 2004]