Equilibrium Question 631
Question: An equilibrium mixture of the reaction $ 2H_2S(g) $ ⇌ $ 2H_2(g)+S_2(g) $ had 0.5 mole $ H_2S $ , 0.10 mole $ H_2 $ and 0.4 mole $ S_2 $ in one litre vessel. The value of equilibrium constant $ (K) $ in mole litre-1 is [AIIMS 1998; IIT 1992; AFMC 1999; UPSEAT 2001]
Options:
A) 0.004
B) 0.008
C) 0.016
D) 0.160
Show Answer
Answer:
Correct Answer: C
Solution:
$ K=\frac{{{[H_2]}^{2}}[S_2]}{{{[H_2S]}^{2}}}=\frac{{{[0.10]}^{2}}[0.4]}{{{[0.5]}^{2}}}=0.016 $
