SATHEE: Equilibrium Question 626

Equilibrium Question 626

Question: An amount of solid $N H_{4} H S$ is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm. pressure. Ammonium hydrogen sulphide decomposes to yield $N H_{3}$ and $H_{2} S$ gases in the flask. When the decomposition reaction reaches equilibrium, the total pressure in the flask rises to 0.84 atm. The equilibrium constant for $N H_{4} H S$ decomposition at this temperature is [AIEEE 2005]

Options:

A) 0.30

B) 0.18

C) 0.17

D) 0.11

Show Answer

Answer:

Correct Answer: D

Solution:

$\underset{a - x}{\underset{a}{N H_{4} H S},},$ ⇌ $\underset{0.5 + x, x}{\underset{0.5 a t m,}{N H_{3, (g)} + H_{2} S_{(g)}},},$ Total pressure $= 0.5 + 2 x = 0.84$ i.e., $x = 0.17$

$K_{p} = P_{N H_{3}} . P_{H_{2} S}$

$= (0.67) ., (0.17)$ =0.1139

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Equilibrium Question 626

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu