SATHEE: Equilibrium Question 620

Equilibrium Question 620

Question: In the gas phase reaction, $C_{2} H_{4} + H_{2}$ ⇌ $C_{2} H_{6}$ , the equilibrium constant can be expressed in units of [CBSE PMT 1992; Pb. PMT 1999]

Options:

A) $l i t r e^{- 1}, m o l e^{- 1}$

B) $l i t r e, m o l e^{- 1}$

C) $m o l e^{2}, l i t r e^{- 2}$

D) $m o l e, l i t r e^{- 1}$

Show Answer

Answer:

Correct Answer: B

Solution:

$K = \frac{[C_{2} H_{6}]}{[C_{2} H_{4}] [H_{2}]} = \frac{[m o l e / l i t r e]}{[m o l e / l i t r e] [m o l e / l i t r e]}$ = litre/mole. or litre mole-1.

Equilibrium Question 620

Question: In the gas phase reaction, $C_{2} H_{4} + H_{2}$ ⇌ $C_{2} H_{6}$ , the equilibrium constant can be expressed in units of [CBSE PMT 1992; Pb. PMT 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Equilibrium Question 620

Question: In the gas phase reaction, C2H4+H2 ⇌ C2H6 , the equilibrium constant can be expressed in units of [CBSE PMT 1992; Pb. PMT 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In the gas phase reaction, $C_{2} H_{4} + H_{2}$ ⇌ $C_{2} H_{6}$ , the equilibrium constant can be expressed in units of [CBSE PMT 1992; Pb. PMT 1999]