Equilibrium Question 599
Question: $ {A_{(g)}}+3{B_{(g)}} $ ⇌ $ 4{C_{(g)}} $ . Starting concentration of A is equal to B, equilibrium concentration of A and C are same. $ K_{c}= $ [Kerala CET 2005]
Options:
A) 0.08
B) 0.8
C) 8
D) 80
E) 1/8
Show Answer
Answer:
Correct Answer: C
Solution:
A + 3B ⇌ 4C a b 0 (a - x) (b - 3x) 4x $ K_{C}=\frac{{{[C]}^{4}}}{[A]{{[B]}^{3}}}=\frac{4x.4x.4x.4x}{(a-x)(b-3x)} $ Given $ a=b,,a-x=4x\Rightarrow a=5x=b $
$ K_{C}=\frac{4x.4x.4x.4x}{(5x-x)(5x-3x)}=\frac{4x.4x.4x.4x}{4x.2x.2x.2x}=8 $ .
