Equilibrium Question 590
Question: For the reaction, $ C{O_{(g)}}+C{l_{2(g)}} $ ⇌ $ COC{l_{2(g)}} $ the $ K_{p}/K_{c} $ is equal to [AIEEE 2004]
Options:
A) $ \sqrt{RT} $
B) $ RT $
C) $ 1/RT $
D) $ 1.0 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ CO(g)+Cl_2(g) $
$ COCl_2(g) $
$ \Delta n=1-2=-1 $
$ K_{p}=K_{c}{{[RT]}^{\Delta n}} $ ;
$ \therefore ,\frac{K_{p}}{K_{c}}={{[RT]}^{-1}}=\frac{1}{RT} $
