Equilibrium Question 576

Question: If $ K_{c} $ is the equilibrium constant for the formation of $ NH_3 $ , the dissociation constant of ammonia under the same temperature will be [DPMT 2001]

Options:

A) $ K_{c} $

B) $ \sqrt{K_{c}} $

C) $ K_c^{2} $

D) $ 1/K_{c} $

Show Answer

Answer:

Correct Answer: D

Solution:

$ NH_3 $ ⇌ $ \frac{1}{2}N_2+\frac{3}{2}H_2 $

$ K_{c}=\frac{{{[N_2]}^{{1}/{2};}}{{[H_2]}^{{3}/{2};}}}{NH_3} $ and $ \frac{1}{2}N_2+\frac{3}{2}H_2 $ ⇌ $ NH_3 $

$ K_{c}=\frac{[NH_3]}{{{[N_2]}^{{1}/{2};}}{{[H_2]}^{{3}/{2};}}} $ So for dissociation $ =\frac{1}{K_{c}} $



NCERT Chapter Video Solution

Dual Pane