Equilibrium Question 568
Question: The equilibrium constant for the reaction $ N_2+3H_2 $ ⇌ $ 2NH_3 $ is $ K, $ then the equilibrium constant for the equilibrium $ NH_3 $ ⇌ $ \frac{1}{2}N_2+\frac{3}{2}H_2 $ is [CBSE PMT 1996; UPSEAT 2001]
Options:
A) $ 1/K $
B) $ 1/K^{2} $
C) $ \sqrt{K} $
D) $ \frac{1}{\sqrt{K}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ K_1 $ for $ N_2+3H_2 $ ⇌ $ 2NH_3 $
$ K_2 $ for $ NH_3 $ ⇌ $ \frac{1}{2}N_2+\frac{3}{2}H_2 $
$ K_1\times K_2=\frac{{{[NH_3]}^{2}}}{[N_2]{{[H_2]}^{3}}}\times \frac{{{[N_2]}^{{1}/{2};}}{{[H_2]}^{{3}/{2};}}}{[NH_3]} $
$ K_1\times K_2=\frac{1}{K_2} $ ; $ K_2=\frac{1}{\sqrt{K_1}} $
