Equilibrium Question 526

Question: A weak monoprotic acid of 0.1 M, ionizes to 1% in solution. What will be the pH of solution [MNR 1988]

Options:

A) 1

B) 2

C) 3

D) 11

Show Answer

Answer:

Correct Answer: C

Solution:

$ [{H^{+}}]=C,.,\alpha $

$ [{H^{+}}]=0.1\times \frac{1}{100}={10^{-3}} $ pH $ =-\log [{H^{+}}]=-\log ,{10^{-3}}=3 $



NCERT Chapter Video Solution

Dual Pane