Equilibrium Question 526
Question: A weak monoprotic acid of 0.1 M, ionizes to 1% in solution. What will be the pH of solution [MNR 1988]
Options:
A) 1
B) 2
C) 3
D) 11
Show Answer
Answer:
Correct Answer: C
Solution:
$ [{H^{+}}]=C,.,\alpha $
$ [{H^{+}}]=0.1\times \frac{1}{100}={10^{-3}} $ pH $ =-\log [{H^{+}}]=-\log ,{10^{-3}}=3 $
