Equilibrium Question 487
Question: The $ pH $ of $ \frac{N}{100} $ HCl would be approximately [CPMT 1971; DPMT 1982, 83; MP PMT 1991; Bihar MEE 1996]
Options:
A) 1
B) 1.5
C) 2
D) 2.5
Show Answer
Answer:
Correct Answer: C
Solution:
$ 0.01,M,HCl={10^{-2}},M,[{H^{+}}],pH=2 $ .