Equilibrium Question 487

Question: The $ pH $ of $ \frac{N}{100} $ HCl would be approximately [CPMT 1971; DPMT 1982, 83; MP PMT 1991; Bihar MEE 1996]

Options:

A) 1

B) 1.5

C) 2

D) 2.5

Show Answer

Answer:

Correct Answer: C

Solution:

$ 0.01,M,HCl={10^{-2}},M,[{H^{+}}],pH=2 $ .



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