SATHEE: Equilibrium Question 472

Equilibrium Question 472

Question: If the $p H$ of a solution is 4.0 at $25^{o} C,$ its $p O H$ would be $(K_{w} = 10^{- 14})$ [MP PMT 1989]

Options:

A) 4.0

B) 6.0

C) 8.0

D) 10.0

Show Answer

Answer:

Correct Answer: D

Solution:

$p H + p O H = 14,, p H = 4.0$

$p O H = 14 - p H$ ; $p O H = 14 - 4.0 = 10.0$

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Equilibrium Question 472

Question: If the pH of a solution is 4.0 at 25oC, its pOH would be (Kw=10−14) [MP PMT 1989]

Options:

Answer:

Solution:

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Question: If the $p H$ of a solution is 4.0 at $25^{o} C,$ its $p O H$ would be $(K_{w} = 10^{- 14})$ [MP PMT 1989]