SATHEE: Equilibrium Question 468

Equilibrium Question 468

Question: The $p H$ of a solution having $[H^{+}] = 10 \times 10^{- 4} m o l e s / l i t r e$ will be [BHU 1981]

Options:

A) 1

B) 2

C) 3

D) 4

Show Answer

Answer:

Correct Answer: C

Solution:

0.001 M HCl $= 10^{- 3}, M, [H^{+}],$

$p H = 3$ .

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Equilibrium Question 468

Question: The pH of a solution having [H+]=10×10−4moles/litre will be [BHU 1981]

Options:

Answer:

Solution:

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Question: The $p H$ of a solution having $[H^{+}] = 10 \times 10^{- 4} m o l e s / l i t r e$ will be [BHU 1981]