SATHEE: Equilibrium Question 467

Equilibrium Question 467

Question: What will be the $p H$ of a solution formed by mixing $40 m l$ of $0.10 M H C l$ with $10 m l$ of $0.45 M N a O H$ [Manipal MEE 1995]

Options:

A) 12

B) 10

C) 8

D) 6

Show Answer

Answer:

Correct Answer: A

Solution:

M.eq. of 0.10 $M H C l = \frac{0.10}{1000} \times 40 = 0.004 M$ M.eq. of 0.45 $M N a O H = \frac{0.45 \times 10}{1000} = 0.0045 M$ Now left $[O H^{-}] = 0.0045 - 0.004$

$= 5 \times 10^{- 4}$ M Total volume = 50 ml. $[O H^{-}] = \frac{5 \times 10^{- 4}}{50} \times 1000$ ; $[O H^{-}] = 1 \times 10^{- 2}$ pOH = 2 ; pH = 14 - pOH = 12.

Equilibrium Question 467

Question: What will be the $p H$ of a solution formed by mixing $40 m l$ of $0.10 M H C l$ with $10 m l$ of $0.45 M N a O H$ [Manipal MEE 1995]

Options:

Answer:

Solution:

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Equilibrium Question 467

Question: What will be the pH of a solution formed by mixing 40ml of 0.10MHCl with 10ml of 0.45MNaOH [Manipal MEE 1995]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: What will be the $p H$ of a solution formed by mixing $40 m l$ of $0.10 M H C l$ with $10 m l$ of $0.45 M N a O H$ [Manipal MEE 1995]