Equilibrium Question 425

Question: Given that the dissociation constant for $ H_2O $ is $ K_{w}=1\times {10^{-14}} $

$ mole^{2}litr{e^{-2}}, $ what is the $ HCl $ of a $ 0.001molarKOH $ solution [MP PET 1995; MP PET/PMT 1998]

Options:

A) $ {10^{-11}} $

B) 3

C) 14

D) 11

Show Answer

Answer:

Correct Answer: D

Solution:

0.001 M KOH solution $ [O{H^{-}}]=0.001,M=1\times {10^{-3}}M $

$ [{H^{+}}]\times [O{H^{-}}]=1\times {10^{-14}} $

$ [{H^{+}}]=\frac{1\times {10^{-14}}}{[O{H^{-}}]} $

$ [{H^{+}}]=\frac{1\times {10^{-14}}}{1\times {10^{-3}}} $

$ =1\times {10^{-14}}\times {10^{+3}} $

$ [{H^{+}}]={10^{-11}} $ M $ pH=11 $



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