Equilibrium Question 411

Question: When 10 ml of 0.1 M acetic acid (pKa=5.0) is titrated against 10 ml of 0.1M ammonia solution (pKb=5.0) , the equivalence point occurs at pH [AIIMS 2005]

Options:

A) 5.0

B) 6.0

C) 7.0

D) 9.0

Show Answer

Answer:

Correct Answer: C

Solution:

pKa = - log Ku, pKb = - log Kb pH = −12[log⁡Ka+log⁡Kw−log⁡Kb]

=−12[−5+log⁡(1×10−14)−(−5)]

=−12[−5−14+5]=−12(−14)=7

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