Equilibrium Question 410

Question: What will be the pH of a 10−8,M,HCl solution [MP PET/PMT 1998; RPET 1999;MP PMT 2000]

Options:

A) 8.0

B) 7.0

C) 6.98

D) 14.0

Show Answer

Answer:

Correct Answer: C

Solution:

H2O ⇌ [H+][OH−] HCl ⇌ [H+][Cl−]

Total [H+]=[H+]H2O+[H+]HCl

=10−7+10−8

=10−7[1+10−1]

[H+]=10−7×1110

pH=−log,[H+]=−log⁡(10−7+1110) ; pH=6.958

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