SATHEE: Equilibrium Question 41

Equilibrium Question 41

Question: $p K_{a}$ of a weak acid is defined as [JIPMER 1999]

Options:

A) log $_{10} K_{a}$

B) $\frac{1}{l o g_{10} K_{a}}$

C) log $_{10} \frac{1}{K_{a}}$

D) -log $_{10} \frac{1}{K_{a}}$

Show Answer

Answer:

Correct Answer: C

Solution:

$p K_{a} = \log_{10} \frac{1}{K_{a}}$

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Equilibrium Question 41

Question: pKa of a weak acid is defined as [JIPMER 1999]

Options:

Answer:

Solution:

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Question: $p K_{a}$ of a weak acid is defined as [JIPMER 1999]