SATHEE: Equilibrium Question 402

Equilibrium Question 402

Question: By adding $20, m l$ $0.1, N, H C l$ to $20, m l$ $0.001, N,$ $K O H,$ the pH of the obtained solution will be [KCET 2000]

Options:

A) 2

B) 1.3

C) 0

D) 7

Show Answer

Answer:

Correct Answer: B

Solution:

20 ml. of 0.1 NHCl = $\frac{0.1}{1000} \times 20 g$ eq. = $2 \times 10^{- 3} g$ eq. 20ml. of 0.001 KOH = $\frac{0.001}{1000} \times 20, g m$ eq. = 2 × $10^{- 5} g$ eq.
$∴$ HCl left unneutralised = $2 (10^{- 3} - 10^{- 5})$

$= 2 \times 10^{- 3} (1 - 0.01)$ = $2 \times 0.99 \times 10^{- 3}$

$= 1.98 \times 10^{- 3} g, e q .$ Volume of solution = 40 ml. \ [HCl] = $\frac{1.98 \times 10^{- 3}}{40} \times 1000 M$ = $4.95 \times 10^{- 2}$

$∴$ pH = $2 -$ log 4.95 = 2 - 0.7 = 1.3.

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Equilibrium Question 402

Question: By adding 20,ml 0.1,N,HCl to 20,ml 0.001,N, KOH, the pH of the obtained solution will be [KCET 2000]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: By adding $20, m l$ $0.1, N, H C l$ to $20, m l$ $0.001, N,$ $K O H,$ the pH of the obtained solution will be [KCET 2000]