Equilibrium Question 365

Question: 0.1 mole of CH3NH2 (Kb = 5 ´ 10-4) is mixed with 0.08 mole of HCl and diluted to one litre. What will be the H+ concentration in the solution’ [IIT 2005]

Options:

A) 8 ´ 10-2 M

B) 8 ´ 10-11 M

C) 1.6 ´ 10-11 M

D) 8 ´ 10-5 M

Show Answer

Answer:

Correct Answer: B

Solution:

CH3NH2 + HCl $ \xrightarrow{{}} $

$ CH_3NH_3^{+}C{l^{-}} $ 0.1 0.08 0 0.02 0 0.08 (Basic buffer solution)

pOH = pKb + log $ \frac{0.08}{0.02} $ = pKb + 0.602 = 3.30 + 0.602= 3.902 \ pH = 10.09 [H+] = 7.99 ´ 10-11 » 8 ´ 10-11 M



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